document.write( "Question 60672This question is from textbook Essential Algebra
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document.write( ": Hi I am having a problem grasping consecutive integers. I do not know how to write out this equation. Any help would be appreciated.
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document.write( "Thanks,
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document.write( "Lee Ann\r
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document.write( "Problem: Twice the sum of the first and third of three consecutive integers is fifteen less than the second integer. Find the integers. \n" );
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Algebra.Com's Answer #41643 by praseena(37)![]() ![]() ![]() You can put this solution on YOUR website! here we have three consecutive numbers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so we can take it as (x-1), x and (x +1 )\r \n" ); document.write( "\n" ); document.write( "sum of the first and third term = x - 1 + x + 1\r \n" ); document.write( "\n" ); document.write( " = x+ x -1 + 1\r \n" ); document.write( "\n" ); document.write( " = 2x\r \n" ); document.write( "\n" ); document.write( "now twicw thw sum of first and third term is = 2 * (2x)\r \n" ); document.write( "\n" ); document.write( " = 4x\r \n" ); document.write( "\n" ); document.write( " now it is given that this 4x is 15 less that the second term\r \n" ); document.write( "\n" ); document.write( "==> 4x = x - 15 \n" ); document.write( " \n" ); document.write( "==> 4x -x = -15 { bringing like terms together )\r \n" ); document.write( "\n" ); document.write( "==> 3X = -15\r \n" ); document.write( "\n" ); document.write( "==> X = -15/3 { dividing both sides by 3 }\r \n" ); document.write( "\n" ); document.write( " x = -5\r \n" ); document.write( "\n" ); document.write( "thus we got the middle term (second term) is -5 \n" ); document.write( "so the first term is x-1 = -5-1\r \n" ); document.write( "\n" ); document.write( " = -6 \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "third term is ( x +1 ) = -5 + 1 \r \n" ); document.write( "\n" ); document.write( " = -4\r \n" ); document.write( "\n" ); document.write( "so the terms are -6, -5 and -4\r \n" ); document.write( "\n" ); document.write( "Bye!!!!!!!!! \n" ); document.write( " |