document.write( "Question 669522: A boat takes 2hours to go 4 miles upstream. It can go 8 miles downstream in the same amount of time. Find the rate of the current and the rate of the boat in still water. (Because the current pushes the boat when it is going downstream, the rate of the boat downstream is the sum of the rate of the boat and the rate of the current. The current slows down the boat when it's going upstream so the rate of the boat upstream is the difference of the rate of the boat and the rate of the current. I need to know the rate of the current and the rate of the boat in still water in MPH. \n" ); document.write( "

Algebra.Com's Answer #416422 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "A boat takes 2hours to go 4 miles upstream.  
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document.write( "It can go 8 miles downstream in the same amount of time of 2hrs.
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document.write( "  r - c = 4/2 = 2mph 
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document.write( "  r + c = 8/2 = 4mph   ||Adding EQs together to elminate c
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document.write( "   2r = 6mph
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document.write( "    r = 3mph  and  c = 1mph \n" );
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