document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=669476>Question 669476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if log sub b of 3 = 0.4771, log sub b of 4 = 0.621, and log sub b of 5 = 0.6990, find the following logarithms:\r<BR>\n" );
document.write( "\n" );
document.write( "1.) log sub b of 120 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #416408 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=416408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if log sub b of 3 = 0.4771, log sub b of 4 = 0.621, and log sub b of 5 = 0.6990, find the following logarithms:\r<BR>\n" );
document.write( "\n" );
document.write( "1.) log sub b of 120<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28b%2C2%29+=+log%28b%2C4%29%2F2+=+0.3105 ALIGN=MIDDLE  ALT=\"log%28b%2C2%29+=+log%28b%2C4%29%2F2+=+0.3105\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "-------<BR>\n" );
document.write( "120 = 2*3*4*5<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "PS  log(4) = 0.6020, not 0.621 (base 10) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );