document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=669447>Question 669447</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A hollow spherical shell has inner diameter 2 cm and outer diameter 4 cm.Determine the volume of the shell. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #416404 by </B><A HREF=/tutors/aboutme.mpl?userid=SATCHI76><B>SATCHI76(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=SATCHI76><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=416404\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here R= 2 cm, r= 1 cm<BR>\n" );
document.write( "Volume =(4/3). Pie. (R^3-r^3)<BR>\n" );
document.write( "       =(4/3). Pie. (2^3-1^3)<BR>\n" );
document.write( "       =(4/3). Pie. (8-1)<BR>\n" );
document.write( "       =(4/3). Pie. 7<BR>\n" );
document.write( "       =(4/3). 22<BR>\n" );
document.write( "       = 88/3 cm^3 </SPAN>\n" );
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