document.write( "Question 669459: Write an equation in standard form for the line described.
\n" ); document.write( " Through (7,9), perpendicular to 5x+y=4 \n" ); document.write( "
Algebra.Com's Answer #416402 by mananth(16946)\"\" \"About 
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5 x + 1 y = 4
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "1 y = -5 x + 4
\n" ); document.write( "Divide by 1
\n" ); document.write( " y = -5 x + 4
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = -5
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal 1/5
\n" ); document.write( "Because m1*m2 =-1
\n" ); document.write( "The slope of the required line will be 1/5
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\n" ); document.write( "m= 1/5 ,point ( 7 , 9 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "9 = 7/ 5 + b
\n" ); document.write( "b= 38/5
\n" ); document.write( "m= 1/5
\n" ); document.write( "The required equation is y = 1/ 5 x + 38/ 5
\n" ); document.write( "m.ananth@hotmail.ca
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