document.write( "Question 669400: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have? \r
\n" ); document.write( "\n" ); document.write( "This is the problem directly from my homework. I'm trying to figure out the system of equations so I can solve the problem. So far I've come up with\r
\n" ); document.write( "\n" ); document.write( " .1d+.05n=5.65 and 2(.1d)+.05n+8=10.45\r
\n" ); document.write( "\n" ); document.write( "but I keep ending up with d= -32 so I must be way off.
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Algebra.Com's Answer #416391 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have? \r
\n" ); document.write( "\n" ); document.write( "This is the problem directly from my homework. I'm trying to figure out the system of equations so I can solve the problem. So far I've come up with\r
\n" ); document.write( "\n" ); document.write( " .1d+.05n=5.65 and 2(.1d)+.05n+8=10.45\r
\n" ); document.write( "\n" ); document.write( "but I keep ending up with d= -32 so I must be way off.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You are off, but not by that much. Looking at what I got and you got, I can see that your 2nd equation should have been .1(2D) + .05(N + 8) = 10.45. This is where your error is. The correct solution is below:\r
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\n" ); document.write( "\n" ); document.write( "Let the original amount of dimes and nickels that he has be D, and N, respectively
\n" ); document.write( "Then: .1D + .05N = 5.65 ----- eq (i)
\n" ); document.write( "Doubling the amount of dimes would make the dimes, 2D
\n" ); document.write( "Increasing the nickels by 8 would make the amount of nickels, N + 8
\n" ); document.write( "Therefore, .1(2D) + .05(N + 8) = 10.45 ------ .2D + .05N + .4 = 10.45 ---- .2D + .05N = 10.05 ----- eq (ii)\r
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\n" ); document.write( "\n" ); document.write( ".1D + .05N = 5.65 ---- eq (i)
\n" ); document.write( ".2D + .05N = 10.05 ---- eq (ii)
\n" ); document.write( "- .1D = - 4.40 --------- Subtracting eq (ii) from eq (i)
\n" ); document.write( "D, or original amount of dimes = \"%28-+4.4%29%2F-+.1\", or \"highlight_green%2844%29\"\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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