document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=58629>Question 58629</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0078603919/algebrahomeworkh>Glenco Mathematics Algebra 1Indiana Edition</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> (Photo reference: carton of 2% milk which has 2% butterfat and picture of carton of whipping cream containing 9% butterfat).\r<BR>\n" );
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document.write( "\"Refer to the graphic at the right\" How much whipping cream and 2% milk should be mixed to obtain 35 gallons of milk with 4% butterfat?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41638 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amt of milk (gal) to be mixed<BR>\n" );
document.write( "Then 35-x=amt of whipping cream (gal) to be mixed<BR>\n" );
document.write( "We know that the amt of butterfat in the milk (x)(.02) plus the amt of butterfat in the whipping cream (35-x)(.09) equals the amt of butterfat in the final mixture (35)(.04). Thus, our equation to solve is:\r<BR>\n" );
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document.write( "(x)(.02)+(35-x)(.09)=(35)(.04) simplifying, we get<BR>\n" );
document.write( ".02x+3.15-.09x=1.4 further simplifying, we have<BR>\n" );
document.write( "-.07x=-1.75<BR>\n" );
document.write( "x=25 gal<BR>\n" );
document.write( "We need 25 gal of milk and 35-25=10 gal of whipping cream <BR>\n" );
document.write( "Hope this helps ----ptaylor </SPAN>\n" );
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