document.write( "Question 669389: Joe is 20,089 days old. I am 5886 days old. When will Joe be exactly twice my age in days? \n" ); document.write( "
Algebra.Com's Answer #416364 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let joe be double my age after x days\r \n" ); document.write( "\n" ); document.write( "after x days \n" ); document.write( "joes' age = (20089+x)\r \n" ); document.write( "\n" ); document.write( "My age = (5886+x)\r \n" ); document.write( "\n" ); document.write( "(20089+x) = 2(5886+x)\r \n" ); document.write( "\n" ); document.write( "920089=11772+2x\r \n" ); document.write( "\n" ); document.write( "920089-11772=2x \n" ); document.write( "8317 =2x \n" ); document.write( "x=8317/2 \n" ); document.write( "x=4158.5\r \n" ); document.write( "\n" ); document.write( "After 4185 days Joe will be double my age.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |