document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=669343>Question 669343</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 10. Twice the larger decreased by three times the smaller is 5. Find the two number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #416345 by </B><A HREF=/tutors/aboutme.mpl?userid=pamalah@yahoo.com><B>pamalah@yahoo.com(10)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pamalah@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=416345\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let L = large<BR>\n" );
document.write( "Let S = small\r<BR>\n" );
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document.write( "System of equations:<BR>\n" );
document.write( "L+S=10  <BR>\n" );
document.write( "2L-3S=5\r<BR>\n" );
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document.write( "L+S=10  (-2)<BR>\n" );
document.write( "2L-3S=5\r<BR>\n" );
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document.write( "-2L+-2S=-20<BR>\n" );
document.write( "2L-3S=5\r<BR>\n" );
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document.write( "-5s=-15<BR>\n" );
document.write( "s=3\r<BR>\n" );
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document.write( "L=7\r<BR>\n" );
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document.write( "L+S=10<BR>\n" );
document.write( "7+3=10 true\r<BR>\n" );
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document.write( "2L-3S=5<BR>\n" );
document.write( "2*7-3*3=5<BR>\n" );
document.write( "14-9=5 true </SPAN>\n" );
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