document.write( "Question 669251: what is cos(2theta) if cos=1/3 and csc<0 \n" ); document.write( "
Algebra.Com's Answer #416328 by lwsshak3(11628)\"\" \"About 
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what is cos(2theta) if cos=1/3 and csc<0
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\n" ); document.write( "csc<0 in quadrants III and IV
\n" ); document.write( "cos>0 in quadrants I and IV
\n" ); document.write( "so, we are working with reference angle in quadrant IV
\n" ); document.write( "cosx=1/3=adjacent side/hypotenuse in quadrant IV where cos>0
\n" ); document.write( "opposite side=√(3^2-1^2)=√(9-1)=√8
\n" ); document.write( "sinx=opposite side/hypotenuse=-√8/3(in quadrant IV where sin<0
\n" ); document.write( "cos2x=cos^2x-sin^2x=1/9-8/9=-7/9
\n" ); document.write( "Check:
\n" ); document.write( "cos^-1=1/3
\n" ); document.write( "x≈70.529º
\n" ); document.write( "2x≈141.05756º
\n" ); document.write( "cos2x≈-0.7777..
\n" ); document.write( "-7/9≈-0.7777..
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