document.write( "Question 60480: The number of bacteria present in a culture after t minutes is given as
\n" ); document.write( "B= 100e^kt. IF there are 5287 bacteria present after 13 minutes, find k.
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Algebra.Com's Answer #41630 by smik(40)\"\" \"About 
You can put this solution on YOUR website!
Good question. Great question. Let's go through it.
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\n" ); document.write( "So, we start of with the equation B=100e^kt, and the fact that B=5287 when t=13. With this in mind we can easily solve for k as shown below:
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\n" ); document.write( "\"5287+=+100e%5E%2813k%29\" (divide both sides by 100)
\n" ); document.write( "\"52.87+=+e%5E%2813k%29\" (natural log of both sides, which cancels out the e)
\n" ); document.write( "\"ln%2852.87%29+=+13k\" (divide both sides by 13)
\n" ); document.write( "\"ln%2852.87%29%2F13+=+k\"
\n" ); document.write( "\"k+=+0.305\" (to three significant figures)
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\n" ); document.write( "Hope all that helps.
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