document.write( "Question 669304: A jar has 190 coins consisiting of nickels, dimes and quarter the value of the coins totals $20. How many nickles, dimes and quarters are in the jar.\r
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document.write( "N + D + Q = 190
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document.write( "5N + 10D + 25Q = 2000
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document.write( "-10N - 10D - 10Q = -1900\r
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document.write( "-5N + 15Q = 100
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document.write( "N - 3Q = -20
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document.write( "N = 3Q - 20\r
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document.write( "other answer is D = 210 - 4Q\r
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document.write( "Q can equal 52 and 7 therefore 7 <= Q <= 52\r
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document.write( "making the possibilities\r
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document.write( "52 Q = 13.00
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document.write( "2 D = .20
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document.write( "136 N = 6.80
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document.write( " 20
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document.write( "similar for 52\r
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document.write( "My question is this, How do I do the same thing for \r
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document.write( "N + D + Q + H = 100 coins nickles, dime, quarters and half dollars
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document.write( "5N + 10D + 25Q + 50H = 1675\r
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document.write( "How do I solve for the possibilities \r
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document.write( "so far i have\r
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document.write( "D = 235 - 4Q - 9H
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document.write( "N = 3Q + 8H - 135 \n" );
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Algebra.Com's Answer #416298 by lynnlo(4176) ![]() You can put this solution on YOUR website! 20 nickels==================$1.00 \n" ); document.write( "10 dimes====================$1.00 \n" ); document.write( "4 quarters==================$1.00 \n" ); document.write( "you got =190 coins \n" ); document.write( " total value==$20.00 \n" ); document.write( "dimes===========nickels====================quarters \n" ); document.write( "50=$5.00 100=$5.00 40=$10.00 \n" ); document.write( " \n" ); document.write( " $5.00+$5.00+$10.00==========$20.00 \n" ); document.write( " 50coins + 100coins +40coins=========190 \n" ); document.write( " |