document.write( "Question 669159: have 5 gallons of glacial acetic acid . need to make a total of 3 gallons of a 30% solution. how many milliliters of distilled wate and how many milliliters of glacial acetic acid are needed to make 3 gallons of 30% solution? please reply to jr8565@ bellsouth.net \n" ); document.write( "
Algebra.Com's Answer #416241 by ankor@dixie-net.com(22740)\"\" \"About 
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have 5 gallons of glacial acetic acid . need to make a total of 3 gallons of a 30% solution.
\n" ); document.write( " how many milliliters of distilled water and how many milliliters of glacial acetic acid are needed to make 3 gallons of 30% solution?
\n" ); document.write( ":
\n" ); document.write( "let x = amt of acid required (in gal)
\n" ); document.write( "the resulting amt is to be 3 gal, therefore
\n" ); document.write( "(3-x) = amt of water required
\n" ); document.write( ":
\n" ); document.write( "x = .3(3)
\n" ); document.write( "x = .9 gal of acid required
\n" ); document.write( "then
\n" ); document.write( "3 -.9 = 2.1 gal of water
\n" ); document.write( ":
\n" ); document.write( "But for some obscure reason, they want the amts to be in milliliters
\n" ); document.write( ":
\n" ); document.write( "1 gal = 3.785 liters which is 3785 milliliter
\n" ); document.write( ":
\n" ); document.write( "Acid: .9(3785) = 3406.5 milliliters
\n" ); document.write( "water: 2.1(3785) = 7948.5 milliliters \n" ); document.write( "
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