document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60651>Question 60651</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I Reduce the following expression to its lowest terms? \r<BR>\n" );
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document.write( "4u^2-36/u^2-2u-15\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41624 by </B><A HREF=/tutors/aboutme.mpl?userid=asha><B>asha(30)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=asha><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41624\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">    4u^2-36/u^2-2u-15<BR>\n" );
document.write( " Numerator=  4(u^2-9) =4(u-3)(u+3)  difference of two squares<BR>\n" );
document.write( "Denominator=u^2-5u+3u-15 splitting the middle term such that sum is -2<BR>\n" );
document.write( "                         and product is 15.\r<BR>\n" );
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document.write( "           =u(u-5)+3(u-5)  taking common terms<BR>\n" );
document.write( "           =(u-5)(u+3) <BR>\n" );
document.write( "the sum is 4(u+3)(u-3)/(u-5)(u+3)<BR>\n" );
document.write( "cancelling common terms we get the answer<BR>\n" );
document.write( "   4(u-3)/(u-5)      <BR>\n" );
document.write( "good luck !!        </SPAN>\n" );
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