document.write( "Question 669237: word problems involving quadratic equation
\n" ); document.write( "the area of a rectangle is 52 square centimeters. find its perimeter when the length is 1 cm more than 3 times its width. \n" ); document.write( "
Algebra.Com's Answer #416232 by nerdybill(7384)\"\" \"About 
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the area of a rectangle is 52 square centimeters. find its perimeter when the length is 1 cm more than 3 times its width.
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\n" ); document.write( "Let w = width
\n" ); document.write( "then
\n" ); document.write( "3w+1 = length
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\n" ); document.write( "width*length = area
\n" ); document.write( "w(3w+1) = 52
\n" ); document.write( "3w^2+w = 52
\n" ); document.write( "3w^2+w-52 = 0
\n" ); document.write( "3w^2-12w+13w-52 = 0
\n" ); document.write( "(3w^2-12w)+(13w-52) = 0
\n" ); document.write( "3w(w-4) + 13(w-4) = 0
\n" ); document.write( "(w-4)(3w+13) = 0
\n" ); document.write( "w = {-13/3, 4}
\n" ); document.write( "toss out the negative value (extraneous) leaving:
\n" ); document.write( "w = 4 cm (width)
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\n" ); document.write( "Length:
\n" ); document.write( "3w+1 = 3(4)+1 = 12+1 = 13 cm
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\n" ); document.write( "Perimeter:
\n" ); document.write( "2(4+13) = 2(17) = 34 cm
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