document.write( "Question 669216: Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean μ = 29.6 kilograms and standard deviation σ = 3.6 kilograms. Let x be the weight of a fawn in kilograms.
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document.write( "Convert the following z intervals to x intervals. (Round your answers to one decimal place.)
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document.write( "(d) −2.17 < z
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document.write( "< x\r
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document.write( "(e) z < 1.28
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document.write( "x <\r
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document.write( "(f) −1.99 < z < 1.44
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document.write( "< x < \n" );
document.write( "
Algebra.Com's Answer #416218 by stanbon(75887) ![]() You can put this solution on YOUR website! Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean μ = 29.6 kilograms and standard deviation σ = 3.6 kilograms. Let x be the weight of a fawn in kilograms. \n" ); document.write( "Convert the following z intervals to x intervals. (Round your answers to one decimal place.) \n" ); document.write( "(d) −2.17 < z \n" ); document.write( "< x \n" ); document.write( "(e) z < 1.28 \n" ); document.write( "x < \n" ); document.write( "(f) −1.99 < z < 1.44 \n" ); document.write( "< x < \n" ); document.write( "----- \n" ); document.write( "Use the form x = z*s + u to convert z-values to x-values \n" ); document.write( "------------------ \n" ); document.write( "Example: \n" ); document.write( "For -2.17 < z \n" ); document.write( "x = -2.17*3.6 + 29.6 \n" ); document.write( "---- \n" ); document.write( "x = 21.788 \n" ); document.write( "Ans: x < 21.788 \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |