document.write( "Question 669185: the sum of the reciprocals of two number is 5/8. four times the reciprocal of the first is twice as much as eight times the reciprocal of the second. find the numbers. \n" ); document.write( "
Algebra.Com's Answer #416210 by ankor@dixie-net.com(22740)\"\" \"About 
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Write an equation for each statement; the two numbers are a & B
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\n" ); document.write( " the sum of the reciprocals of two number is 5/8.
\n" ); document.write( "\"1%2Fa\" + \"1%2Fb\" = \"5%2F8\"\r
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\n" ); document.write( "\n" ); document.write( " four times the reciprocal of the first is twice as much as eight times the reciprocal of the second.
\n" ); document.write( "\"4%281%2Fa%29\" = \"2%288%2Fb%29\"
\n" ); document.write( "which is
\n" ); document.write( "\"4%2Fa\" = \"16%2Fb\"
\n" ); document.write( "cross multiply
\n" ); document.write( "4b = 16a
\n" ); document.write( "divide both sides by 4
\n" ); document.write( "b = 4a
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\n" ); document.write( "find the numbers.
\n" ); document.write( "Back to the 1st equation, replace b with 4a
\n" ); document.write( "\"1%2Fa\" + \"1%2F%284a%29\" = \"5%2F8\"
\n" ); document.write( "multiply by 8a, results:
\n" ); document.write( "8 + 2 = 5a
\n" ); document.write( "10 = 5a
\n" ); document.write( "a = 2
\n" ); document.write( "then
\n" ); document.write( "b = 4*2
\n" ); document.write( "b = 8
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\n" ); document.write( "See if that checks out
\n" ); document.write( "\"1%2F2\" + \"1%2F8\" = \"5%2F8\"
\n" ); document.write( "\"4%2F8\" + \"1%2F8\" = \"5%2F8\"
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