document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60638>Question 60638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you please help me whith this problem<BR>\n" );
document.write( "64. Minimizing cost. A company uses the formula C(x) = 0.02x^2 – 3.4x + 150 to model the unit cost in dollars for producing x stabilizer bars.  For what number of bars id the unit cost at its minimum?  What is the unit cost at level of production? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41621 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41621\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> C(x) = 0.02x^2 - 3.4x + 150<BR>\n" );
document.write( "Differentiating the above with respect to x,<BR>\n" );
document.write( "C '(x) = (0.02)(2)x - 3.4 + 0 [because differential of a constant is zero.]-(1)<BR>\n" );
document.write( "Equating C '(x) to zero,<BR>\n" );
document.write( "==> (0.02)(2)x - 3.4 = 0<BR>\n" );
document.write( "==> 0.04x - 3.4 = 0<BR>\n" );
document.write( "==> 0.04x = 3.4<BR>\n" );
document.write( "==> 0.04x/0.04 = 3.4/0.04<BR>\n" );
document.write( "==> x = 85\r<BR>\n" );
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document.write( "Now differentiating equation (1) again we get..<BR>\n" );
document.write( "C '' (x) = 0.04 which is positive.\r<BR>\n" );
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document.write( "So x = 85 units the unit cost is minimum.<BR>\n" );
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