document.write( "Question 669060: an investor put a total of 3500 in two mutal funds. one fund had a profit of 6% and the other 4% profit, for a total of 170 profit. how much was invested in each fund? \n" ); document.write( "
Algebra.Com's Answer #416140 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Part I 6.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 4.00% per annum ------------ Amount invested = y =
\n" ); document.write( " 3500
\n" ); document.write( "Interest----- 170
\n" ); document.write( "
\n" ); document.write( "Part I 6.00% per annum ---x
\n" ); document.write( "Part II 4.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 3500 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "6.00% x + 4.00% y= 170
\n" ); document.write( "Multiply by 2
\n" ); document.write( "6 x + 4 y= 17000.00 --------2
\n" ); document.write( "Multiply (1) by -6
\n" ); document.write( "we get
\n" ); document.write( "-6 x -6 y= -21000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -2 y= -4000
\n" ); document.write( "divide by -2
\n" ); document.write( " y = 2000
\n" ); document.write( "Part I 6.00% $ 1500
\n" ); document.write( "Part II 4.00% $ 2000 \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "1500 --------- 6.00% ------- 90.00
\n" ); document.write( "2000 ------------- 4.00% ------- 80.00
\n" ); document.write( "Total -------------------- 170.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
\n" ); document.write( "
\n" );