document.write( "Question 669149: John drove to a distance city in 6 hours. When he returned, there was less traffic and the trip took only 5 hours. If John averaged 12 mph faster on the return trip, how fast did John travel in each direction? \n" ); document.write( "
Algebra.Com's Answer #416136 by mananth(16946)\"\" \"About 
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speed = x mph forward trip -6 hours
\n" ); document.write( "return trip speed = x+12 mph----- 5 hours\r
\n" ); document.write( "\n" ); document.write( "Distance is same obviously and he took the same route.\r
\n" ); document.write( "\n" ); document.write( "D=rt\r
\n" ); document.write( "\n" ); document.write( "6x=5(x+12)\r
\n" ); document.write( "\n" ); document.write( "6x=5x+60
\n" ); document.write( "x=60\r
\n" ); document.write( "\n" ); document.write( "Forward speed = 60 mph
\n" ); document.write( "return speed = 60+12= 72 mph\r
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