document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=669155>Question 669155</A>: <I><SPAN STYLE=\"word-break: break-all;\"> WHAT IS THE AREA OF THE CIRCLE IF THE SQUARE INSCRIBED OF AREA 57 SQUARE METER </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #416134 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=416134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length of the diagonal = diamter of the circle\r<BR>\n" );
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document.write( "area = 57m^2\r<BR>\n" );
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document.write( "Area of square = l^2  where l is the length of the side of square.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=l+=+sqrt%2857%29 ALIGN=MIDDLE  ALT=\"l+=+sqrt%2857%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The diagonal can be found out by Pythagoras theorem<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28side1%29%5E2%2B%28side2%29%5E2=+hypotenuse%5E2 ALIGN=MIDDLE  ALT=\"%28side1%29%5E2%2B%28side2%29%5E2=+hypotenuse%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28sqrt%2857%29%29%5E2+%2B+%28sqrt%2857%29%29%5E2=+diagonal%5E2 ALIGN=MIDDLE  ALT=\"%28sqrt%2857%29%29%5E2+%2B+%28sqrt%2857%29%29%5E2=+diagonal%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=57%2B57+=+diagonal%5E2 ALIGN=MIDDLE  ALT=\"57%2B57+=+diagonal%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=114+=+diagonal+%5E2 ALIGN=MIDDLE  ALT=\"114+=+diagonal+%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=diagonal+=+sqrt%28114%29 ALIGN=MIDDLE  ALT=\"diagonal+=+sqrt%28114%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area+of+cirlce=+pi%2A%28d%5E2%2F4%29 ALIGN=MIDDLE  ALT=\"Area+of+cirlce=+pi%2A%28d%5E2%2F4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  where d is the diameter\r<BR>\n" );
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document.write( "Area = pi*114/4\r<BR>\n" );
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document.write( "area = 89.57 m^2\r<BR>\n" );
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