document.write( "Question 669131: find two consecutive odd integers such that one third of the smaller plus twice the larger equals 7 more than the sum of the two numbers. Explain your answer and show your work. \n" ); document.write( "
Algebra.Com's Answer #416104 by mananth(16946) You can put this solution on YOUR website! let the odd integers be x & x+2\r \n" ); document.write( "\n" ); document.write( "(1/3)x + 2(x+2)= x+x+2+7 \n" ); document.write( "x/3 + 2x+4 = 2x+9\r \n" ); document.write( "\n" ); document.write( "multiply equation by 3 \n" ); document.write( "x+6x+12=6x+27 \n" ); document.write( "x= 27-12 \n" ); document.write( "x=15\r \n" ); document.write( "\n" ); document.write( "The numbers are 15 & 17\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |