document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=60634>Question 60634</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0078213479/algebrahomeworkh>alegbra concepts and applications</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve\r<BR>\n" );
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document.write( "x/2 + 5x/10 = -2\r<BR>\n" );
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document.write( "thank you so much </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41610 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41610\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x/2 + 5x/10 = -2\r<BR>\n" );
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document.write( "10 is the LCD for the denominators on the left side.<BR>\n" );
document.write( "Multiplying both the sides of the equation by 10 we get..<BR>\n" );
document.write( "(x/2)*10 + (5x/10)*10 = (-2)*(10)<BR>\n" );
document.write( "==> 5x + 5x = -20<BR>\n" );
document.write( "==> 10x = -20<BR>\n" );
document.write( "==> 10x/10 = -20/10<BR>\n" );
document.write( "==> x = -2\r<BR>\n" );
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document.write( "Good Luck!!! </SPAN>\n" );
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