document.write( "Question 669106: Factor by grouping\r
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Algebra.Com's Answer #416076 by jim_thompson5910(35256)\"\" \"About 
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\"xy-2x%2B5y-10\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%28xy-2x%29%2B%285y-10%29\" Group the terms in two pairs\r
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\n" ); document.write( "\n" ); document.write( "\"x%28y-2%29%2B5%28y-2%29\" Factor out the GCF \"x\" out of the first group. Factor out the GCF \"5\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%28y-2%29\" Since we have the common term \"y-2\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"xy-2x%2B5y-10\" factors to \"%28x%2B5%29%28y-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"xy-2x%2B5y-10=%28x%2B5%29%28y-2%29\"
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