document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1369>Question 1369</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of the circle circumscribed about regular heptagon ABCDEFG is 196(pie). The bisectors of angles A and D intersect at P. Find AP. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #416 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=416\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Sol: Let the radius of the circumscribed circle be r,<BR>\n" );
document.write( "      By area of the circle = pi r^2 = 196 pi, so r^2 = 196, r = 14<BR>\n" );
document.write( "      Since the bisector of any angle of a regular polygon must pass through <BR>\n" );
document.write( "      the center of the circumscribed circle. Hence,the bisectors of angles <BR>\n" );
document.write( "     A and D intersect at P which is just the center of the circle. <BR>\n" );
document.write( "     So,we have AP = r = 14...Answer </SPAN>\n" );
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