document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=668869>Question 668869</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man is three times as old as his son and six years ago the product of their age was 288. Find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #415938 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=415938\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=son's age; x-6=son's age 6 years ago<BR>\n" );
document.write( "Then 3x=father's age: 3x-6=father's age 6 years ago<BR>\n" );
document.write( "Now we are told the following:<BR>\n" );
document.write( "(x-6)(3x-6)=288 expand left side using FOIL<BR>\n" );
document.write( "3x^2-6x-18x+36=288<BR>\n" );
document.write( "3x^2-24x+36=288  divide each term by 3<BR>\n" );
document.write( "x^2-8x+12=96 subtract 96 from each side<BR>\n" );
document.write( "x^2-8x-84=0  quadratic in standard form and it can be factored<BR>\n" );
document.write( "(x+6)(x-14)=0<BR>\n" );
document.write( "x=-6----------------No good--can't have negative ages<BR>\n" );
document.write( "x=14------------------son's present age<BR>\n" );
document.write( "3x=42---------------------father's present age<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "(14-6)(42-6)=288<BR>\n" );
document.write( "8*36=288<BR>\n" );
document.write( "288=288\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor </SPAN>\n" );
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