document.write( "Question 668891: how do you graph the inequality y>2abolute value sign x+3 close absolute value sign -3 \n" ); document.write( "
Algebra.Com's Answer #415924 by stanbon(75887)\"\" \"About 
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how do you graph the inequality y>2absolute value sign x+3 close absolute value sign -3
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\n" ); document.write( "Since the absolute value can never be negative it bottoms out
\n" ); document.write( "at x+3 = 0, or x = -3
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\n" ); document.write( "y = 2|x+3|-3
\n" ); document.write( "Plot a few points around x = -3, then draw the graph which is the boundary
\n" ); document.write( "for the inequality.
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\n" ); document.write( "If x = -6 y = 3
\n" ); document.write( "If x = -4 y = -1
\n" ); document.write( "If x = -2 y = -1
\n" ); document.write( "If x = -3 y = -3 (that is the bottom point
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\n" ); document.write( "Draw the v-shaped boundary by connecting those points.
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\n" ); document.write( "Since you want y to GREATER than the boundary shade the area
\n" ); document.write( "ABOVE the boundary.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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