document.write( "Question 668883: At O Haire Airport in Chicago, Cheryl and Will are walking to their gate (at the same Speed) to catch their flight to Akron, Ohio. Since Will want a window seat he steps onto the moving sidewalk and continues to walk while Cheryl uses the stationary sidewalk. if the sidewalk moves at 1 meter per second and Will saves 50 Seconds covering the 300 meter building what is their walking speed \n" ); document.write( "
Algebra.Com's Answer #415917 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Since Will want a window seat he steps onto the moving sidewalk and continues to walk while Cheryl uses the stationary sidewalk. if the sidewalk moves at 1 meter per second and Will saves 50 Seconds covering the 300 meter building what is their walking speed \n" ); document.write( "---------- \n" ); document.write( "Note: The assumption seems to be that they walk at the same rate. \n" ); document.write( "------------- \n" ); document.write( "Will's DATA: \n" ); document.write( "rate = 1+x meters/sec ; distance 300 meters ; time = 300/(1+x) seconds \n" ); document.write( "------ \n" ); document.write( "Cheryl's DATA: \n" ); document.write( "rate = x meters/sec ; distance = 300 meters ; time = 300/x seconds \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "Cheryl time - Will time = 50 seconds \n" ); document.write( "---- \n" ); document.write( "300/x - 300/(1+x) = 50 \n" ); document.write( "----- \n" ); document.write( "1/x - 1/(1+x) = 1/6 \n" ); document.write( "6(1+x) - 6x = x(1+x) \n" ); document.write( "---- \n" ); document.write( "x^2+x-6 = 0 \n" ); document.write( "(x+3)(x-2) = 0 \n" ); document.write( "Positive solution: \n" ); document.write( "x = 2 meters/sec (Their walking speed) \n" ); document.write( "=========================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |