document.write( "Question 668879: a metallurgist has one alloy containing 20% copper and another containing 70% copper. These can be blended to get a mixture between 20 and 70%. \r
\n" ); document.write( "\n" ); document.write( "a metallurgist has one alloy containing 20% copper and another containing 70% copper. These can be blended to get a mixture between 20 and 70%. use your model to calculate the mixture needed for 50lbs of 40% copper.
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Algebra.Com's Answer #415907 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "a metallurgist has one alloy containing 20% copper and another containing 70% copper. These can be blended to get a mixture between 20 and 70%.
\n" ); document.write( "Create a model to determine how many pounds of each alloy to mix to achieve
\n" ); document.write( "a given weight and copper percentage\"highlight%28P%29\": \".70x%2B+.20y=+P%28x%2By%29\"
\n" ); document.write( "calculate the mixture needed for 50lbs of 40% copper.
\n" ); document.write( " \".70x+%2B+.20%2850-x%29+=+.40%2A50\" \"y+=+%2850-x%29\"
\n" ); document.write( " .50x = .20*50
\n" ); document.write( " x = 20lbs 70% and 30lbs 20% \n" ); document.write( "
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