document.write( "Question 668792: solve the natural logarithmic equation algebraically. Approximate the result to three decimal places.
\n" ); document.write( "1.) ln x + ln ( x + 3 ) = 1
\n" ); document.write( "2.) ln ( x + 1 ) - ln ( x - 2 ) = ln x^2 \r
\n" ); document.write( "\n" ); document.write( "Please help me! I need it by today I have been trying I don't get it:(
\n" ); document.write( "

Algebra.Com's Answer #415850 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do #1 to get you started.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "ln( x ) + ln ( x + 3 ) = 1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "ln( x(x + 3) ) = 1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x(x + 3) = e^1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x(x + 3) = e\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x^2 + 3x = e\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x^2 + 3x - e = 0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x^2 + 3x - 2.71828 = 0 (note: e is roughly 2.71828...)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now use the quadratic formula to solve for x. In this case, a = 1, b = 3, and c = 2.71828\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%283%29%2B-sqrt%28%283%29%5E2-4%281%29%28-2.71828%29%29%29%2F%282%281%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3%2B-sqrt%289-%28-10.87312%29%29%29%2F%282%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3%2B-sqrt%289%2B10.87312%29%29%2F%282%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3%2B-sqrt%2819.87312%29%29%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3%2Bsqrt%2819.87312%29%29%2F2\" or \"x+=+%28-3-sqrt%2819.87312%29%29%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3%2B4.4579278%29%2F2\" or \"x+=+%28-3-4.4579278%29%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+0.7289639\" or \"x+=+-3.7289639\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the possible answers are \"x+=+0.7289639\" or \"x+=+-3.7289639\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "However, plugging in \"x+=+-3.7289639\" yields a negative argument in the log, which is not allowed. So we must toss out this x value.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the only solution (to 3 decimal places) is \"x+=+0.729\"
\n" ); document.write( "
\n" );