document.write( "Question 668792: solve the natural logarithmic equation algebraically. Approximate the result to three decimal places.
\n" ); document.write( "1.) ln x + ln ( x + 3 ) = 1
\n" ); document.write( "2.) ln ( x + 1 ) - ln ( x - 2 ) = ln x^2 \r
\n" ); document.write( "\n" ); document.write( "Please help me! I need it by today I have been trying I don't get it:(
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Algebra.Com's Answer #415844 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
ln(x) + ln(x+3) = 1\r
\n" ); document.write( "\n" ); document.write( "ln(x*(x+3) = 1\r
\n" ); document.write( "\n" ); document.write( "e^(ln(x*(x+3)) = e^1\r
\n" ); document.write( "\n" ); document.write( "x^2 + 3x = e\r
\n" ); document.write( "\n" ); document.write( "x^2 +3x -e = 0\r
\n" ); document.write( "\n" ); document.write( "By quadratic formula you get x = \"%281%2F2%29sqrt%289%2B4e%29+-3\" = .729 as the only positive solution. Since ln(x) where x is negative is undefined.\r
\n" ); document.write( "\n" ); document.write( "ln(x+1) - ln(x-2) = ln(x^2)\r
\n" ); document.write( "\n" ); document.write( "ln((x+1)/(x-2)) = ln(x^2)\r
\n" ); document.write( "\n" ); document.write( "e^ln((x+1)/(x-2)) = e^ln(x^2)\r
\n" ); document.write( "\n" ); document.write( "(x+1)/(x-2) = x^2\r
\n" ); document.write( "\n" ); document.write( "x+1 = x^3 - 2x^2\r
\n" ); document.write( "\n" ); document.write( "x^3 -2x^2 -x -1 = 0\r
\n" ); document.write( "\n" ); document.write( "Find that x = 2.55 is the only real solution.\r
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