document.write( "Question 668792: solve the natural logarithmic equation algebraically. Approximate the result to three decimal places.
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document.write( "1.) ln x + ln ( x + 3 ) = 1
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document.write( "2.) ln ( x + 1 ) - ln ( x - 2 ) = ln x^2 \r
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document.write( "Please help me! I need it by today I have been trying I don't get it:( \n" );
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Algebra.Com's Answer #415844 by swincher4391(1107)![]() ![]() You can put this solution on YOUR website! ln(x) + ln(x+3) = 1\r \n" ); document.write( "\n" ); document.write( "ln(x*(x+3) = 1\r \n" ); document.write( "\n" ); document.write( "e^(ln(x*(x+3)) = e^1\r \n" ); document.write( "\n" ); document.write( "x^2 + 3x = e\r \n" ); document.write( "\n" ); document.write( "x^2 +3x -e = 0\r \n" ); document.write( "\n" ); document.write( "By quadratic formula you get x = \n" ); document.write( "\n" ); document.write( "ln(x+1) - ln(x-2) = ln(x^2)\r \n" ); document.write( "\n" ); document.write( "ln((x+1)/(x-2)) = ln(x^2)\r \n" ); document.write( "\n" ); document.write( "e^ln((x+1)/(x-2)) = e^ln(x^2)\r \n" ); document.write( "\n" ); document.write( "(x+1)/(x-2) = x^2\r \n" ); document.write( "\n" ); document.write( "x+1 = x^3 - 2x^2\r \n" ); document.write( "\n" ); document.write( "x^3 -2x^2 -x -1 = 0\r \n" ); document.write( "\n" ); document.write( "Find that x = 2.55 is the only real solution.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |