document.write( "Question 668740: Form a polynomial f(x) with real coefficients having the given degree and zeros.\r
\n" ); document.write( "\n" ); document.write( "Degree 5; Zeros:2; -i; -6+i
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Algebra.Com's Answer #415816 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
FACT: All imaginary roots come in conjugate pairs.\r
\n" ); document.write( "\n" ); document.write( "So we have 2,-i,i, -6+i, -6-i.\r
\n" ); document.write( "\n" ); document.write( "Then (x-2)[(x+i)(x-i)][(x-(-6+i))(x-(-6-i))] = (x-2)(x^2+1)(x^2+12x+37) = x^5+10x^4+14x^3-64x^2+13x-74
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