document.write( "Question 668275: An accountant rides the bus part of the way to work everyday and walks the rest of the way. The bus averages 40mph, and the accountant walks at a speed of 5mph. The distance from home to work is 19 miles, and the total time for the trip is 2hrs.
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Algebra.Com's Answer #415804 by ankor@dixie-net.com(22740)\"\" \"About 
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rides the bus part of the way to work everyday and walks the rest of the way.
\n" ); document.write( " The bus averages 40mph, and the accountant walks at a speed of 5mph.
\n" ); document.write( " The distance from home to work is 19 miles, and the total time for the trip is 2hrs.
\n" ); document.write( "Find how far the accountant walks
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\n" ); document.write( "let w = the distance walked
\n" ); document.write( "then
\n" ); document.write( "(19-w) = the distance on the bus
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\n" ); document.write( "Write time equation; time = dist/speed
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\n" ); document.write( "Walk time + ride time = 2 hrs
\n" ); document.write( "\"w%2F5\" + \"%28%2819-w%29%29%2F40\" = 2
\n" ); document.write( "Multiply by 40 to clear the denominators resulting in:
\n" ); document.write( "8w + 19 - w = 40(2)
\n" ); document.write( "7w = 80 - 19
\n" ); document.write( "7w = 61
\n" ); document.write( "w = 61/7
\n" ); document.write( "w ~ 8.7 miles walking
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\n" ); document.write( "Check this by finding the times walking and busing (19-8.7=10.3)
\n" ); document.write( "8.7/5 = 1.74 hrs
\n" ); document.write( "10.3/40 = .26 hrs
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\n" ); document.write( "total time: 2 hrs
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