document.write( "Question 668705: If the perimeter of a rectangle is 68 meters and the length is 14 meters more than the width, what are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #415780 by swincher4391(1107)![]() ![]() You can put this solution on YOUR website! P = 2l + 2w\r \n" ); document.write( "\n" ); document.write( "l = w + 14\r \n" ); document.write( "\n" ); document.write( "68 = 2(w+14) + 2w\r \n" ); document.write( "\n" ); document.write( "68 = 2w + 28 + 2w\r \n" ); document.write( "\n" ); document.write( "40 = 4w\r \n" ); document.write( "\n" ); document.write( "w = 10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "l = 10 + 14 = 24\r \n" ); document.write( "\n" ); document.write( "24x10 \n" ); document.write( " |