document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=668702>Question 668702</A>: <I><SPAN STYLE=\"word-break: break-all;\">  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #415777 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=415777\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6x^2-x -35\r<BR>\n" );
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document.write( "First, see if this is easily factorable. \r<BR>\n" );
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document.write( "Find two numbers such that they multiply to 6*-35 = -210, but add up to -1. After thinking about this you get -15 and 14.\r<BR>\n" );
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document.write( "So rewrite -x as -15x + 14x.\r<BR>\n" );
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document.write( "6x^2 -15x +14x-35\r<BR>\n" );
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document.write( "Group each pair and factor pairwise.\r<BR>\n" );
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document.write( "(6x^2-15x) + (14x-35)\r<BR>\n" );
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