document.write( "Question 668666: Of two consecutive integers, four times the lesser exceeds the three times the greater by 30. What are the integers?
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Algebra.Com's Answer #415763 by amazingrace333(11)\"\" \"About 
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Solve by representing the two consecutive integers as x, and x+1
\n" ); document.write( "Four times the lesser would be 4x.
\n" ); document.write( "Three times the greater would be 3(x+1).
\n" ); document.write( "Now what else do you know to solve this?...that 4x is 30 more than 3(x+1) or in equation format:
\n" ); document.write( "4x = 30 + 3(x+1)
\n" ); document.write( "Now simplify and solve as follows:
\n" ); document.write( "4x = 30 + 3x +3
\n" ); document.write( "4x = 33 + 3x
\n" ); document.write( "4x - 3x = 33 + (3x - 3x)
\n" ); document.write( "x = 33
\n" ); document.write( "Check your answer:
\n" ); document.write( "4x = 4(33) = 132
\n" ); document.write( "x+1 = 34
\n" ); document.write( "3(34) = 102
\n" ); document.write( "132 - 102 = 30
\n" ); document.write( "So the correct integers are 33 and 34.
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