document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=668685>Question 668685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangle has a peremiter of 165 cm. The first side is 65 cm less than twice the second side. The third side is 10 cm less than the second side. Write and solve an equation to find the length of each side of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #415758 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=415758\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For sides a,b,c perimeter = a+b+c\r<BR>\n" );
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document.write( "Let a,b,c be the 1st,2nd,3rd sides respectively.\r<BR>\n" );
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document.write( "a = 2b - 65<BR>\n" );
document.write( "c = b - 10\r<BR>\n" );
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document.write( "a+b+c = 2b -65 + b + b-10 = 165\r<BR>\n" );
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document.write( "4b = 240\r<BR>\n" );
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document.write( "b =  60\r<BR>\n" );
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document.write( "If b = 60 then:\r<BR>\n" );
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document.write( "a = 2(60) - 65 = 55\r<BR>\n" );
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document.write( "c = 60-10 = 50\r<BR>\n" );
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document.write( "So our sides are 55,60,50. </SPAN>\n" );
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