document.write( "Question 668663: Find the mean and standard deviation of the following probability distribution:
\n" ); document.write( " x
\n" ); document.write( " 1
\n" ); document.write( " 2
\n" ); document.write( " 3
\n" ); document.write( "
\n" ); document.write( "P(x)
\n" ); document.write( " 0.1
\n" ); document.write( " 0.8
\n" ); document.write( " 0.1
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #415738 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
mean = E[X] = x*P(x) for each x = 1*.1 + 2*.8 + 3* .1 = .1 + 1.6 + .3 = \"highlight%282%29\"\r
\n" ); document.write( "\n" ); document.write( "Calculate E[X^2] in order to find Variance. E[X^2] = 1^2 * .1 + 2^2 *.8 + 3^2 * .1 = .1 + 3.2 + .9 = 4.2\r
\n" ); document.write( "\n" ); document.write( "Var[X] = E[X^2] - E[X]^2 = 4.2 - 2^2 = 4.2 - 4 = .2\r
\n" ); document.write( "\n" ); document.write( "SD[X] = sqrt(Var[X]) = sqrt(.2) = \"highlight%28.4472%29\"
\n" ); document.write( "
\n" );