document.write( "Question 668607: don is three times as old as david and the sum of their ages is 52. find their ages? \n" ); document.write( "

Algebra.Com's Answer #415727 by ReadingBoosters(3246) $\"\"$ $\"About$

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Establish the variables
\n" ); document.write( "x = don
\n" ); document.write( "y = david
\n" ); document.write( "...
\n" ); document.write( "Given
\n" ); document.write( "x = 3y
\n" ); document.write( "x+y=52
\n" ); document.write( "...
\n" ); document.write( "3y + y = 52
\n" ); document.write( "4y = 52
\n" ); document.write( " $\"highlight_green%28y+=+13%29\"$ years old for David
\n" ); document.write( "...
\n" ); document.write( "x = 3(13) = $\"highlight_green%28x+=+39%29\"$ years old for Don
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