document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=668610>Question 668610</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Twice the complement of an acute angle exceeds an obtuse angle by 10 degrees. Twice the supplement of the obtuse angle is 15 degrees more than the supplement of the acute angle. Find the acute angle and the obtuse. <BR>\n" );
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document.write( "I have:\r<BR>\n" );
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document.write( "2(90-x)=(90+x)+10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #415700 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=415700\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the acute. Let y be the obtuse.\r<BR>\n" );
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document.write( "2(90-x) = y + 10<BR>\n" );
document.write( "2(180-y) = (90-x) + 15\r<BR>\n" );
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document.write( "180 - 2x = y + 10 -->  170 - 2x = y<BR>\n" );
document.write( "360 - 2y = x + 15\r<BR>\n" );
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document.write( "360 -2(170-2x) = (90-x)+15\r<BR>\n" );
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document.write( "360 - 340 +4x = 105-x<BR>\n" );
document.write( "-85 = -5x\r<BR>\n" );
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document.write( "x = 17 degrees\r<BR>\n" );
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document.write( "170 - 2(17) = y\r<BR>\n" );
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document.write( "170 - 34 = 136 degrees\r<BR>\n" );
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document.write( "17 degrees - acute<BR>\n" );
document.write( "136 degrees - obtuse </SPAN>\n" );
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