document.write( "Question 668572: -5 I 6a + 2 I = -15\r
\n" ); document.write( "\n" ); document.write( "I = absolute valu sign\r
\n" ); document.write( "\n" ); document.write( "I was taught to drop the absolute value sign, set up two equations-- DISABLED_event_one= to -15 and DISABLED_event_one= to 15 and then solve for a. So for this problem, I wasn't sure if I should drop the absolute value sign and then it would be -5 x 6a + 2 = -15 and -5 x 6a + 2 = 15 OR if I should first distribute the -5 as if the absolute value signs were parentheses. Thanks so much for your help.
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Algebra.Com's Answer #415683 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Don't do anything with the absolute value quantity until you get rid of the coefficient outside of it. Further, absolute value bars are NOT parentheses, so you can't just willy-nilly distribute across them. The only thing left is do divide both sides by the coefficient outside. THEN you can drop the bars and make two equations.\r
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\n" ); document.write( "\n" ); document.write( "By the way: Capital Is don't make good absolute value bars. Hold the shift key and type the backslash key (the one above the Enter key). That pipe symbol -- | -- makes a perfect absolute value bar.\r
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\n" ); document.write( "\n" ); document.write( "For more on rendering math into plain text, see:\r
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\n" ); document.write( "\n" ); document.write( "Formatting Math\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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