document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=668572>Question 668572</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -5 I 6a + 2 I = -15\r<BR>\n" );
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document.write( "I = absolute valu sign\r<BR>\n" );
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document.write( "I was taught to drop the absolute value sign, set up two equations-- DISABLED_event_one=  to -15 and  DISABLED_event_one=  to 15 and then solve for a.  So for this problem, I wasn't sure if I should drop the absolute value sign and then it would be -5 x 6a + 2 = -15 and -5 x 6a + 2 = 15 OR if I should first distribute the -5 as if the absolute value signs were parentheses.  Thanks so much for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #415680 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=415680\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -5 I 6a + 2 I = -15\r<BR>\n" );
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document.write( "I = absolute valu sign<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "-5|6a + 2| = -15<BR>\n" );
document.write( "|6a + 2| = 3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "6a+2 = 3<BR>\n" );
document.write( "6a = 1<BR>\n" );
document.write( "a = 1/6<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "6a+2 = -3<BR>\n" );
document.write( "6a = -5<BR>\n" );
document.write( "a = -5/6<BR>\n" );
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