document.write( "Question 668565: THe perimeter of a rectangular photograph is 22 inches. The length of the photograph is 1 inch more than the width. What are the dimensions of the photograph? \n" ); document.write( "
Algebra.Com's Answer #415668 by swincher4391(1107)\"\" \"About 
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\"P+=+2l+%2B+2w\" where l is the length and w is the width
\n" ); document.write( "The length of the photo is 1 inch more than the width: l = w+1\r
\n" ); document.write( "\n" ); document.write( "\"22+=+2%28w%2B1%29+%2B+2w\"
\n" ); document.write( "\"22+=+2w+%2B+2+%2B+2w\"
\n" ); document.write( "\"22+=+4w+%2B+2\"
\n" ); document.write( "\"20+=+4w\"
\n" ); document.write( "\"w+=+5\"\r
\n" ); document.write( "\n" ); document.write( "l = w+1 ---> l = 5 +1 = 6\r
\n" ); document.write( "\n" ); document.write( "So 6x5.
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