document.write( "Question 668487: rebecca is four years older than jake. Five years ago she was twice as old as he was. Find their ages now.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #415634 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
Let r be the age of Rebecca. Let j be the age of Jake.\r
\n" ); document.write( "\n" ); document.write( "Rebecca is four years older than Jake: r = j+4\r
\n" ); document.write( "\n" ); document.write( "Five years ago she was twice as old as he was: r-5 = 2(j-5)\r
\n" ); document.write( "\n" ); document.write( "Substitute j+4 for r.\r
\n" ); document.write( "\n" ); document.write( "j+4-5 = 2(j-5)\r
\n" ); document.write( "\n" ); document.write( "j-1 = 2j -10\r
\n" ); document.write( "\n" ); document.write( "9 = j\r
\n" ); document.write( "\n" ); document.write( "r = 9 +4 = 13\r
\n" ); document.write( "\n" ); document.write( "So Jake is 9 and Rebecca is 13.
\n" ); document.write( "
\n" );