document.write( "Question 668378: if the side of the triangle have measures 2x+5, 3x-2 and 6x-7. what are the possible values of x?
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Algebra.Com's Answer #415524 by Edwin McCravy(20081)\"\" \"About 
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document.write( "The sum of any two sides of a triangle must be greater than the third side.\r\n" );
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document.write( "1.   (2x+5) + (3x-2) > 6x-7\r\n" );
document.write( "           2x+5+3x-2 > 6x-7\r\n" );
document.write( "                5x+3 > 6x-7\r\n" );
document.write( "                  -x > -10\r\n" );
document.write( "                   x < 10\r\n" );
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document.write( "2.   (2x+5) + (6x-7) > 3x-2\r\n" );
document.write( "           2x+5+6x-7 > 3x-2\r\n" );
document.write( "                8x-2 > 3x-2\r\n" );
document.write( "                  5x > -4\r\n" );
document.write( "                   x > \"-4%2F5\"\r\n" );
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document.write( "3.   (3x-2) + (6x-7) > 2x+5\r\n" );
document.write( "           3x-2+6x-7 > 2x+5\r\n" );
document.write( "                9x-9 > 2x+5\r\n" );
document.write( "                  7x > 14\r\n" );
document.write( "                   x > 2\r\n" );
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document.write( "All three inequalities x < 10, x > \"-4%2F5\", x > 2 must be satisfied\r\n" );
document.write( "by x.\r\n" );
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document.write( "x > \"-4%2F5\" is automatically guaranteed by x > 2, so we can eliminate \r\n" );
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document.write( "that one and we have x < 10 and x > 2 which can be written as\r\n" );
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document.write( "                 2 < x < 10\r\n" );
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document.write( "Edwin
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