document.write( "Question 668359: In an acute triangle ABC,an altitude AD is drawn. Find the area of triangle ABC if AB=15, AC=18, and BD=10. \n" ); document.write( "
Algebra.Com's Answer #415473 by mananth(16946)\"\" \"About 
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Since AD is the altitude to base BC we have to find AD & DC\r
\n" ); document.write( "\n" ); document.write( "Two right triangles are formed .
\n" ); document.write( "ABD & ACD\r
\n" ); document.write( "\n" ); document.write( "In triangle ABD
\n" ); document.write( "BD= 10
\n" ); document.write( "AB= 15\r
\n" ); document.write( "\n" ); document.write( "Apply Pythagoras theorem
\n" ); document.write( "AB is the hypotenuse
\n" ); document.write( "\"15%5E2-10%5E2=+AD%5E2\"\r
\n" ); document.write( "\n" ); document.write( "225-100=AD^2
\n" ); document.write( "125 = AD^2
\n" ); document.write( "\"AD+=+5+sqrt%285%29\"\r
\n" ); document.write( "\n" ); document.write( "We have AC= 18
\n" ); document.write( "AD= \"5sqrt%285%29\"\r
\n" ); document.write( "\n" ); document.write( "\"DC%5E2=+18%5E2-%285sqrt%285%29%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"DC%5E2=324-125\"\r
\n" ); document.write( "\n" ); document.write( "\"DC%5E2=199\"\r
\n" ); document.write( "\n" ); document.write( "\"DC+=+sqrt%28199%29\"\r
\n" ); document.write( "\n" ); document.write( "BD+DC= BC\r
\n" ); document.write( "\n" ); document.write( "\"BC+=+10+%2Bsqrt%28199%29\"\r
\n" ); document.write( "\n" ); document.write( "Area of triangle = 1/2 base * altitude
\n" ); document.write( "=\"1%2F2+%2A+%2810%2Bsqrt%28199%29%29%2A5sqrt%285%29\"\r
\n" ); document.write( "\n" ); document.write( "By using calculator you will get 134.76 sq. cm\r
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