document.write( "Question 668301: Two joggers are 2 km apart. If they jog toward each other they will meet in 12 minutes. If they jog in the same direction the faster one will overtake the slower one in 2 hours. At what speed do the joggers jog? \n" ); document.write( "
Algebra.Com's Answer #415467 by mananth(16946)\"\" \"About 
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Jogger A = x km/h
\n" ); document.write( "Jogger B = ykm/h\r
\n" ); document.write( "\n" ); document.write( "jogging towards
\n" ); document.write( "speed = (x+y)
\n" ); document.write( "D=2
\n" ); document.write( "..................... 12 mins = 1/5 hour
\n" ); document.write( "2/(x+y) =1/5\r
\n" ); document.write( "\n" ); document.write( "x+y =10.....................(1)\r
\n" ); document.write( "\n" ); document.write( "in same direction\r
\n" ); document.write( "\n" ); document.write( "speed = x-y\r
\n" ); document.write( "\n" ); document.write( "time = 2 hours\r
\n" ); document.write( "\n" ); document.write( "distance = 2\r
\n" ); document.write( "\n" ); document.write( "2/(x-y)=2
\n" ); document.write( "x-y =1...................(2)\r
\n" ); document.write( "\n" ); document.write( "add (1) & (2)
\n" ); document.write( "2x=11
\n" ); document.write( "x= 5.5 Jogger A speed\r
\n" ); document.write( "\n" ); document.write( "x+y=10
\n" ); document.write( "5.5+y=10
\n" ); document.write( "y=11-4.5
\n" ); document.write( "y=4.5 km/h Jogger B speed
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