document.write( "Question 668182: Please help me with this question:
\n" ); document.write( "Gena walked 160 feet in 40 seconds on a moving walkaway. Against the walkaway, she was able to walk the same distance in 80 seconds. What is the rate at which Gena walked, and what is the rate of the walkaway?
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Algebra.Com's Answer #415374 by ankor@dixie-net.com(22740)\"\" \"About 
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Gena walked 160 feet in 40 seconds on a moving walkaway.
\n" ); document.write( " Against the walkaway, she was able to walk the same distance in 80 seconds.
\n" ); document.write( " What is the rate at which Gena walked, and what is the rate of the walkaway?
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\n" ); document.write( "Let g = Gena's walking rate (ft/sec
\n" ); document.write( "Let w = the walkway rate
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\n" ); document.write( "Write a distance equation for each scenario; dist = time * speed
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\n" ); document.write( "40(g+w) = 160
\n" ); document.write( "and
\n" ); document.write( "80(g-w) = 160
\n" ); document.write( "we can simplify both these equations, divide the 1st one by 40, the 2nd one by 80
\n" ); document.write( "g + w = 4
\n" ); document.write( "g - w = 2
\n" ); document.write( "------------addition eliminates w, find g
\n" ); document.write( "2g = 6
\n" ); document.write( "g = 3 ft/sec is Gina's walking rate
\n" ); document.write( "and
\n" ); document.write( "3 + w = 4
\n" ); document.write( "w = 4 - 3
\n" ); document.write( "w = 1 ft/sec is the walkway rate
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\n" ); document.write( "See if that flies:
\n" ); document.write( "40(3 + 1) = 160
\n" ); document.write( "and
\n" ); document.write( "80(3 -1) = 80 \n" ); document.write( "
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