document.write( "Question 668047: what is the awnser to the question \" is |x-3| equal to or greater than 2 \"
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Algebra.Com's Answer #415319 by Adrianne15(25) $\"\"$ $\"About$

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|x-3|≥ 2
\n" ); document.write( "To solve, get rid of the absolute value signs and then show the two cases:
\n" ); document.write( "x-3 ≥ 2 or -(x-3)≥ 2
\n" ); document.write( "x≥ 2+3 or -x+3≥ 2
\n" ); document.write( "x≥5 or -x≥-1
\n" ); document.write( "x≥5 or x≤1 (remember that when you multiply/divide an inequality by a negative number, you switch the sign) \n" ); document.write( "

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