document.write( "Question 667749: A motorist starts from city A at 2:00 P.M. and travels to city B at an average speed of 30 miles/hour. After resting at B for one hour, he returns over the same route at an average speed of 40 miles/hour and arrives at A that evening at 6:30 P.M. Determine the distance between A and B. \n" ); document.write( "
Algebra.Com's Answer #415286 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A motorist starts from city A at 2:00 P.M. and travels to city B at an average speed of 30 miles/hour.
\n" ); document.write( " After resting at B for one hour, he returns over the same route at an average
\n" ); document.write( " speed of 40 miles/hour and arrives at A that evening at 6:30 P.M.
\n" ); document.write( " Determine the distance between A and B.
\n" ); document.write( ":
\n" ); document.write( "let d = distance from A to B
\n" ); document.write( ":
\n" ); document.write( "From the information given, we know the total time from 2:00 to 6:30 = 4.5 hrs
\n" ); document.write( "However, the total travel time was 1 hr less; 3.5 hrs
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "To time + return time = 3.5 hrs
\n" ); document.write( "\"d%2F30\" + \"d%2F40\" = 3.5
\n" ); document.write( "multiply by 120, to clear the denominators, results:
\n" ); document.write( "4d + 3d = 120(3.5)
\n" ); document.write( "7d = 420
\n" ); document.write( "d = 420/7
\n" ); document.write( "d = 60 mi from A to B
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding the time each way
\n" ); document.write( "60/30 = 2 hrs
\n" ); document.write( "60/40 = 1.5 hrs
\n" ); document.write( "---------------
\n" ); document.write( "total time 3.5 hrs
\n" ); document.write( "
\n" );